You have a 26.3 % (by mass) solution of ethanol (CH_3CH_2OH) in water. What is t

Question

You have a 26.3 % (by mass) solution of ethanol (CH_3CH_2OH) in water. What is the mole fraction of ethanol? You have a 0.925 molality solution of C_6H_12O_6 in water. If the density of the solution is 1.12 g/mL, what is the molarity of the solution? Concentrated sulfuric acid is 18.4 M and 98% by weight. Calculate the density of the sulfuric acid. Fill in the blank: properties only depend on the number of solute particles to solvent particles and not what the solute is made out of. Calculate the osmotic pressure (in torr) of 6.00 L of an aqueous 0.108 M solution at 30. C, if the solute concerned is totally ionized into three ions (e.g., it could be Na_2SO_4 or MgCl_2).

Explanation / Answer

Answer:

Ethanol = 26.3 %

water = 100 - 26.3 = 73.7 %

Percentage is consider as its weight.

Ethanol:

Ethanol moles = weight / molecular weight [Ethanol molecular weight = 46]

moles = 26.3/46

= 0.5717

Water moles = weight / molecular weight

= 73.7 / 18 [water molecular weight = 18]

= 4.094

Ethanol mole fraction = Ethanol moles / (Ethanol moles + water moles)

   = 0.5717 / (0.5717 + 4.094)

= 0.5717 / 4.6657

= 0.1225

Water mole fraction = water moles / (Ethanol moles + water moles)

= 4.094 / (0.5717 + 4.094)

= 4.094 / 4.6657

= 0.8774

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