A total protein assay was performed using four protein standards. The following

Question

A total protein assay was performed using four protein standards. The following is a list of the absorbance value of each standard Using the absorbance values and the concentration of each standard complete the appropriate standard curve. If a patient sample was also analyzed at the same time that the standards were analyzed and had an absorbance value of 0.580, what would the total protein concentration of the sample be? If another patient sample was also analyzed at the same time that the standards were analyzed and had an absorbance value of 0.250, what would the total protein concentration of the sample be?

Explanation / Answer

In the graph, Y-axis indicates absorbance and X-axis depicts concentration. That is, according to the trendline equation y = 0.0638x + 0.003 obtained from the graph, 1 absorbance unit (1 Y = Y) is equal to 0.0638 units on X-axis (concentration) plus 0.003.

Ans. 53. Absorbance of the unknown 1 (sample from patient 1) = 0.580

Putting, y = 0.580 in trendline equation

            0.580 = 0.0638 x + 0.003

            Or, x = (0.580 – 0.003) / 0.0638 = 9.04

Thus, [protein] in unknown 1 = 9.04 mg/dL

Ans. 54. Absorbance of the unknown 2 (sample from patient 2) = 0.250

Putting, y = 0.250 in trendline equation

            0.250 = 0.0638 x + 0.003

            Or, x = (0.250 – 0.003) / 0.0638 = 3.87

Thus, [protein] in unknown 2 = 3.87 mg/dL

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