this was giving by professor to help 23.00 Figure 18.2: Bomb Calorimeter Focus Q
ID: 1059643 • Letter: T
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this was giving by professor to help
23.00 Figure 18.2: Bomb Calorimeter Focus Questions 1) How much energy is released when food burns in the body? 2) How is the caloric content of food determined? Procedure: Part 1: Determination of the Calorimeter Constant 3.00 g of glucose was placed on the sample holder in a bomb calorimeter. The initial temperature inside the calorimeter was 24.90 C. After the ignition of the sample, the temperature was monitored. The maximum temperature was 29.20 C. Using the data in the appendix of the textbook, determine AH for the combustion of glucose (eq. 1). Determine the calorimeter constant. Part 2: Energy Content ofVarious Snacks Copy the data in the table below into a spreadsheet. Calculate the energy content in units of Cal/oz based on the mass and temperature data. Show one sample calculation.
Explanation / Answer
calorimeter constant = 9.83kJ/oC =2.347 Kcal/oC
heat released when 2.41 gm oreo cookies is burnt = 2.347 Kcal/oC *(30.92-26.12)oC = 11.265 Cal
heat released when 1 serving (34gm) cookies is burnt = 11.265 KCal*34/2.41 = 158.93 Cal (Kcal=cal)
% error = (160-158.93)/160 *100 = 0.67 %
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Calculation for microwave popcorn :
hea t released in burning 2.29 gm = 2.347cal/oC * (29.95-25.76) = 9.83393 Cal
calorie per serving = 9.83393 Cal* 30gm/2.29 gm =128.83 Cal
Error % = (130-128.83)/130 *100 = 0.9 %
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Calculations for crunchy cheetos :
heat released in burning 2.21 gm = 2.347cal/oC * (30.49-25.13) = 12.58 Cal
calorie per serving (1oz= 28.35gm) = 12.58 Cal* 28.35gm/2.21 gm =161.38 Cal
erroe% = 160-161.38/160 *100 = 0.86 %
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Calculation for beef jerky:
heat released in burning 2.23 gm = 2.347cal/oC * (29.54-25.89) = 8.56 Cal
calorie per serving (1oz= 28.35gm) = 8.56 Cal* 28.35gm/2.23 gm =108.90 Cal
% error = |80-108.90|/80 *100 = 36.13 %
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Calculation of iol-roated peanuts:
heat released in burning 2.45 gm = 2.347cal/oC * (31.79-25.64) = 14.43 Cal
calorie per serving (1oz= 28.35gm) = 14.43 Cal* 28.35gm/2.45 gm =167.02 Cal
error % = 170-167.02/170 *100 = 1.75 %
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Higest energy content = iol-roasted peanuts and lowest is beef jerky
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