this was never answered fully the first time. POST-LAB QUESTIONS Show al work fo

Question

this was never answered fully the first time.

POST-LAB QUESTIONS Show al work for fll credit 1. Some of sowly Reas dropped very quickly as the solution evaporated and some are of eaporation to the strength of the intermolecular forces. Explai n your reasoning in of recording temperature wersvr process used in cal cess of recording temperature versus time as completed in this experiment is s to the lorimetry. That process can be used to directly calculate the enthalpy of a system. Why couldn't you calculate the enthalpy of this system directly using the data you collected?

Explanation / Answer

1. evaporation is inversly proportion to the intermolecular force.

stronger the intermolecukar force slower will be the evaporation or temperature drop slowly or vice versa

2. note: there is no information regarding the experiment.

3. heat vaporization = mass of the molecule * specific heat* temperature difference + latent heat * mass of the substance.

so, mass of the molecule plays an important role.

1. PbSO4 : 303.26 g/mol

2. mole number = 0.65 mole/lit * 0.04 lit = 0.026 mole

weight = 0.026 mole *303.26 g/mol = 7.88 gm

3. Na2SO4 = 142.04 g/mol

4.mole number =0.35 mole/lit* 0.1 lit = 0.035 mole

weight = 4.97 gm

5. Pb(NO3)2 : 331.2 g/mol

6. mole = 0.4 mole/lit * 1 lit = 0.4 mole

weight = 132.48 gm

7. NaNO3 : 84.9947 g/mol

8. 135.5 gm naNO3 = 1.59 mole

molarity = 1.59 mole / 0.5 lit = 3.18 M

9. a. mole of Na2SO4 : 0.5 mole/lit * 0.006 lit = 0.003 mole

b. mole = 0.5*0.008 = 0.004 mole

c.0.003 mole

d. 0.004 mole

e. Na2SO4 is limitimg reagent.

so mass of PbSO4 = 0.003 mole* molar mass = 0.909 gm

f. % recovery = (0.78/0.909)*100 = 85.80 %

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.