The following table shows the results of a complementation test for eye color mu

Question

The following table shows the results of a complementation test for eye color mutations in Drosophila. How many genes are involved and which mutations are in the same gene? Assuming no recombination takes place, what are the possible phenotypes of the F2 generation that result from crossing the offspring of the vermillion and carnation mutant strains? Show the chromosomal configuration of this F2 generation.

Mutation white garnet ruby vermillion cherry coral apricot buff carnation
white - + + + - - - - +
garnet - + + + + + + +
ruby - + + + + + +
vermillion - + + + + +
cherry - - - - +
coral - - - +
apricot - - +
buff - +
carnation -

Explanation / Answer

The answer above I believe is incorrect.

Look at the (--) signs reading the table from left to right to identify which mutations are on the same gene. We are only interested in the (--) symbol. If it has a symbol, write it down. Then move to the row below. If it's been written down, don't repeat!

Gene 1: white, cherry, coral, apricot, buff

Gene 2: garnet

Gene 3: ruby

Gene 4: vermillion

Gene 5: carnation

Following the rules, we see there are five genes!

Possible phenotypes of the F2:

vermillion x carnation (P1)

Since the vermillion and carnation genes are on different chromosomes we can expect:

_v+_____c__

_v____c+_

where v stands for vermillion and c for carnation, + denotes wildtype.

Mutation white garnet ruby vermillion cherry coral apricot buff carnation white - + + + - - - - + garnet - + + + + + + + ruby - + + + + + + vermillion - + + + + + cherry - - - - + coral - - - + apricot - - + buff - + carnation -

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