How to calculate average molarity of NaOH solution and the % relative average de

Question

How to calculate average molarity of NaOH solution and the % relative average deviation. i (Body) Data Tables: Mass of pure KHP taken (g) Initial burette reading (mLD Final burette reading (mL) Volume of NaOH used (mL) Molarity of NaOH solution Average molarity of NaOH solution relative average deviation C. #502. Styles Styles Pane Trial 2 Trial 3 Trial 1 0.4161g 0.4114g 0.4024g 0.00mL 0.00mL 0.00mL 24.51 mL 24.62 mL 27.48 mL 24.51 mL 24 62mL 27.48 mL 0.08219M 0,08287M 0.0717M Trial 1 Trial 2 Trial 3

Explanation / Answer

Average molarity of NaOH solution:

Procedure:

Take individual molarity of solution, add them and divide by 3 (Total number of trials)

(0.0717 + 0.08219 + 0.08287)/3 = 0.23676/3=0.07892M

Calcaulation of %relative average deviation

Procedure:

Add the difference of each individual result and the average. If the difference is negative, drop the negative sign.

(0.0717 - 0.07892) + (0.08219 - 0.07892) + (0.08287 - 0.07892) = 0.00722 + 0.00327+ 0.00395

= 0.01444

Divide your above value by the sum of the mean of the data(0.07892) and the number of individual results (3).

=0.01444/(0.07892 x 3) = 0.061

Multiply your answer by 100.

= 100 x 0.061 = 6.1%.

The relative average deviation of your data is 6.1%

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