The a pale yellow solid, NH_4HS, decomposes readily to give H_2S and NH_3 as sho

Question

The a pale yellow solid, NH_4HS, decomposes readily to give H_2S and NH_3 as shown below: NH_4HS(s) Equilibrium H_2S(g) + NH_3(g) What is the partial pressure equilibrium constant. K_p for the reaction given that the partial pressure of H_2S (g) gas in an equilibrium mixture at 50 degree C is 0.65 atm. If the value of the partial pressure equilibrium constant, k_p, for the reaction: 2SO_3(g) Equilibrium 2SO_2(g) + O_2(g) is 0.11 at 873 K, what is the value of K_c for the reaction? (R = 0.08206 L middot atm/mol middot K)

Explanation / Answer

7. When the partial pressure of [H2S] = 0.65 atm

which is equal to the partial pressure of [NH3]

The Kp becomes

Kp = [H2S][NH3]

      = (0.65)^2

      = 0.4225

8. Kc = Kp/(RT)^dn

dn = 3-2 = 1

T = 873 K

we get,

Kc = 0.11/(0.08206 x 873)

     = 0.0015

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