Is the heat of neutralization the Mine for any strong and reacting with any stro

Question

Is the heat of neutralization the Mine for any strong and reacting with any strong base? Explain and write a net ionic equation. If concentrated hydrochloric acid is 12 M explain how you would prepare 80 ml of a 1.5 M solution (i.e. What volumes would you use?) Also record your answer on the data page for Part I. If sodium hydroxide pellets are used, explain how you would prepare 80 ml of a 1.5 M sodium hydroxide solution. (i.e. What mass and volume you use?) Also record your answer on the data page for Part I. If concentrated hydrochloric acid is 12 M explain how you would prepare 100 ml of a 0.5 M solution. (i.e, What volumes would you use?) Also record your answer on the data page for Part III.

Explanation / Answer

5. All strong acids and strong bases are strong electrolytes . They are completely ionisable in aquoeus solution.

     NaOH is strong base

     HCl is strong acid

HCl (aq) + NaOH (aq) --------> NaCl (aq) + H2O(l)

H+(aq) +Cl- (aq) + Na+ (aq) +OH- (aq) --------> Na+(aq) +Cl- (aq) + H2O(l)

Removal of spectator ions to get net ionic equation

H+(aq) +OH- (aq) --------> H2O(l) net ionic equation

6.   Before dilution                                                       After dilution

     M1 = 12M                                                            M2 = 1.5M

     V1   =                                                                   V2   = 80ml

            M1V1   = M2V2

             V1     = M2V2/M1

                        = 1.5*80/12   = 10ml

water volume = V2-V1 = 80-10 = 70ml

b. HCl + NaOH --------> NaCl + H2O

     no of moles of HCL = molarity * volume in L

                                    = 12*0.01 = 0.12 moles

   mass of HCl              = 0.12*36.5   = 4.38g

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.