My teacher says the answer is B, but I don\'t know how to explain why. The stand

Question

My teacher says the answer is B, but I don't know how to explain why.

The standard reduction potentials (E") Fumarate 2H+ + 2e- succinate E-+0.031 V E": +0.029 V [FAD] + 2H+ 2e- [FADH2] If 1 M each of succinate, fumarate, FAD, and FADH2 were mixed together in a beaker in the presence of succinate dehydrogenase what would happen? . A. Succinate would become reduced; FADH2 would become oxidized B. Fumarate would become reduced; FADH2 would become oxidized C. Succinate would become oxidized; FAD would become reduced D. Fumarate would become oxidized; FAD would become reduced E. Succinate would become oxidized; FAD would

Explanation / Answer

The half cell which has higher the reduction potential undergoes reduction and the other undergoes oxidation.

So, Reduction potential of Fumerate = 0.031 V

ad reduction potential of FAD = 0.029 V

Hence, Fumerate undergoes reduction and FAD undergoes oxidation.

So (B) is your answer.

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