Vanadium(IV) species that have the V=O group have quite distinct spectra. What i
ID: 1055376 • Letter: V
Question
Vanadium(IV) species that have the V=O group have quite distinct spectra. What is the d-electron configuration of V(IV)? The most symmetrical of such complexes are [VOL_5] with C_av symmetry, with the O atom on the z-axis. What are the symmetry species of the five d orbitals in [VOL_5] complexes? How many d-d bands are expected in the spectra of these complexes? A band near 24 000 cm^-1 in these complexes shows vibrational progressions of the V=O vibration, implicating an orbital involving V=O bonding. Which d-d transition is a candidate? (See C.J. Ballhausen and H.B. Gray, Inorg. Chem., 1962, 1, 111.)Explanation / Answer
The electronic configuration of vanadium = [Ar] 4s2 3d3.
So the electronic configuration of V(IV) will be [Ar] 3d1
Thee are 8 symmetry element in the given compound
one identity element (E)
two C4 axis
one C2 axis
two sigma v plane
two sigma d plane
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