There are many hydrated salts. Use a handbook of chemical data to find the numbe

Question

There are many hydrated salts. Use a handbook of chemical data to find the number of water molecules bound per formula unit in the common hydrates of the following salts: Cobalt (II) chloride, CoCl_2 ___ Tin(II) chloride, SnCl_2 ___ Chromium (II) chloride, CrCl_2 ___ Chromium (III) chloride, CrCl_3 ___ Copper (II) chloride, CuCl_2 ___ For 1.00 g samples of any two of the hydrates you examined in Question 2 above, calculate for each the samples what mass of water would be expected to be released if the samples were heated strength.

Explanation / Answer

Answer -

1) Cobalt(II) chloride = Cobalt(II) chloride hexahydrate (CoCl•6HO), (6 molecules of water bound per formula unit).

2) Tin (II) chloride = Tin(IV) chloride dihydrate (SnCl2.2H2O) (2 molecules of water bound per formula unit).

3) Chromium (II) chloride = It is anhydrous but readily dissolves in water to give Chromium (II) chloride tetrahydrate (CrCl2. 4H2O) (4 molecules of water bound per formula unit).

4) Chromium (III) chloride = Chromium(III) chloride hexahydrate (CrCl3 · 6H2O) (6 molecules of water bound per formula unit).

5) Copper (II) chloride = Copper(II) chloride dihydrate (CuCl2 · 2H2O) (2 molecules of water bound per formula unit).

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