The nonionized from of an acid indicator is yellow and its anion is blue The K o

Question

The nonionized from of an acid indicator is yellow and its anion is blue The K of this indicator is 10^-9 What will be the approximate PH range over which this indicator change color? S-7 3 - 5 8 - 10 9 - 11 4 - 6 The Ksp for Fe(10_3)_3 is 10^14 we mix two solutions of equal volume one containing 10^-2 M Fe^t and one contacting 10^-2 M IO_3 ions at 25 degree C which one of following statement is true No precipitate from because No precipitate from because No precipitate from because No precipitate from because Which of following solubility product expression is covet K_sp(cas) = [Cu^+2][S^2-] K_si (Ag_1s) = [Ag^+2] [s^2-] Kso(caF_2) = [Ca^+2][F]^2} K_sp(As_3 As_04) = [Ag^+]^3[AsO_4^3-]

Explanation / Answer

(2) When ionic product exceeds solubility product then precipitate will form.

Fe(IO3)3 ----> Fe3+ + 3IO3-

Q = [Fe3+][IO3-]3

   = 10-2 M x ( 10-2M)3

    = 10-8 M3

Given solubility product, Ksp = 10-14

Since Q > Ksp , precipitate will form

So option (c) is correct.

(3) Ksp of CuS = [Cu2+] [S2-]

    Ksp of Ag2S = [Ag+]2 [S2-]

   Ksp of CaF2 = [Ca2+][F-]2

    Ksp of Bi2O3 = [Bi3+]2 [O2-]3

    Ksp of Ag3AsO4 = [Ag+]3 [AsO43-]

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