Answer the following questions: a). The heat of fusion of ice is 6.00 kJ/mol. Fi
ID: 1050976 • Letter: A
Question
Answer the following questions:
a). The heat of fusion of ice is 6.00 kJ/mol. Find the number of photons of wavelength = 6.27 10-6 m that must be absorbed to melt 3.00 g of ice
b). The energy required to ionize potassium is 419 kJ/mol. What minimum frequency of light is required to ionize potassium?
c). An X-ray photon of wavelength 0.920 nm strikes a surface. The emitted electron has a kinetic energy of 936 eV. What is the binding energy of the electron in kJ/mol? [KE = .5 mv2; 1 electron volt (eV) = 1.602 10-19 J]
Explanation / Answer
a)
number of mol of Ice = mass/molar mass
= 3/18
= 1/6 mol
heat required = heat of fusion * number of mol
= 6.00 KJ/mol * (1/6)mol
= 6.00 KJ
= 6000 J
energy of 1 photon = h*c/wavelength
= (6.626*10^-34)*(3*10^8)/(6.27*10^-6)
=3.17*10^-20 J
number of photon = 6000 J / (3.17*10^-20)
= 1.89*10^23
Answer: 1.89*10^23
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