Which statement correctly describes this ion? (a) The hybridization of N is sp^2

Question

Which statement correctly describes this ion? (a) The hybridization of N is sp^2, the N-O bond order is less than 1 1/2. and the N-S bond order is greater than 1 1/2; the S-N-O angle is about 120 degree. (b) The hybridization of N is sp^2: the N-O bond order is 1 1/2, and the N-S bond order is 1 1/2; the S-N-O angle is about 120 degree. (c) The hybridization of N is sp^3, the N-O bond order is less than 1 1/2, and the N-S bond order is greater than 1 1/2; the S-N-O angle is about 109 degree. (d) The hybridization of N is sp^2; the N-O bond order is greater than 1 1/2, and the N-S bond order is less than 1 1/2; the S-N-O angle is about 120 degree. (e) The hybridization ofN is sp^3; the N-O bond order is 1 1/2, and the N-S bond order is 1 1/2; the S-N-O angle is about 109 degree. Based upon the Lewis structure below the correct description of the formal charge on Br and the oxidation state of Br is:

Explanation / Answer

19. For the given Lewis diagram for NOS^2- moelcules

the correct statement would be,

(c) the Nitrogen has an sp3 hybridization, N-O bond order is less than 1 1/2 and N-S bond order greater than 1 1/2

20. Looking at the given Lewis diagram for BrF5,

(a) formal charge = 0 and oxidation state = +5

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