You have been asked to prepare 100.0 inL of a buffer solution that is 0.150 M in

Q: You have been asked to prepare 100.0 inL of a buffer solution that is 0.150 M in

Q1 V = 100 mL = 0.1 L [HA] = 0.15 [A-] =0.25 find mass of each component required pH = pKa + log(A-/HA) pKa = 4.75 acetic acid] = MV = 0.15*0.1 = 0.015 mol mass of acid = mol*MW = 0.015*60 = 0.9 g of acid acetate = MV = 0.25*0.1 = 0.025 mol mass of acetate = mol*Mw = 0.025 *82.0343 = 2.050 g of sodium acetate

ID: 1050495 • Letter: Y

Question

You have been asked to prepare 100.0 inL of a buffer solution that is 0.150 M in acetic acid and 0.250 M in sodium acetate. Calculate the grams of each component that you would weigh out. Show your work below. Grams CH_3COOH Grams NaOOCCH_3 To 20.0 mL of the buffer in question 1, you add 1.0 mL of 1.00 M NaOH. Write the chemical equation for the neutralization reaction. Calculate the mmol of each reactant and product before the reaction occurs and after the reaction has occurred. To 20.0 mL of the buffer in question 1, you add 1.0 mL of 1.00 M HC1. Write the chemical equation for the neutralization reaction. Calculate the mmol of each reactant and product before the reaction occurs and after the reaction has occurred.

Explanation / Answer

V = 100 mL = 0.1 L

[HA] = 0.15

[A-] =0.25

find mass of each component required

pH = pKa + log(A-/HA)

pKa = 4.75

acetic acid] = MV = 0.15*0.1 = 0.015 mol

mass of acid = mol*MW = 0.015*60 = 0.9 g of acid

acetate = MV = 0.25*0.1 = 0.025 mol

mass of acetate = mol*Mw = 0.025 *82.0343 = 2.050 g of sodium acetate

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