Nitrogen and hydrogen react to form ammonia, like this: N_2 (g) + 3H_2 (g) right

Question

Nitrogen and hydrogen react to form ammonia, like this: N_2 (g) + 3H_2 (g) rightarrow 2NH_3 (g) Imagine 155. mmol of NH_3 are added to an empty flask, and then answer the following question. What is the rate of the reverse reaction before any NH_3 has been added to the flask? Zero greater than zero, but less than the rate of the forward reaction. Greater than zero, and equal to the rate of the forward reaction. Greater than zero, and greater than the rate of the forward reaction. What is the rate of the reverse reaction just after the NH_3 has been added to the flask? Zero greater than zero, but less than the rate of the forward reaction. Greater than zero, and equal to the rate of the forward reaction. Greater than zero and greater than the rate of the forward reaction. What is the rate of the reverse reaction at equilibrium? Zero Greater than zero, but less than rate of the forward reaction. Greater than zero and equal to the rate of the forward reaction. Greater than zero, and greater than the rate of the forward reaction. How much NH_3 is the flask at equilibrium? None. Some but less than 155. mmol. 155.mmol. More than 155. mmol.

Explanation / Answer

1. rate of the reverse reaction before adding any ammonia is zero as there is no other gas in the flask.

2. After ammonia is added to the empty flask, rate of the reation will be greater than zero and greater than forward reaction as amount of NH3 present is much greater than amount of N2 or H2.

Answer : last option

3.at equilibrium rate of forward and reverse reaction will be same.

Answer : third option

4. At equilibrium the flask will contain NH3, N2 and H2. so, the concentration of NH3 will be less than 155mmol.

answer : 2nd option

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