State 2 differences you will expect to see in the electronic spectrum of bromine

Question

State 2 differences you will expect to see in the electronic spectrum of bromine gas and bromine dissolved in a solvent (Bromine absorbs maximum at wavelength between 400 and 500nm). Explain the differences. State 2 differences you will expect to see in the electronic spectrum of bromine gas and bromine dissolved in a solvent (Bromine absorbs maximum at wavelength between 400 and 500nm). Explain the differences. State 2 differences you will expect to see in the electronic spectrum of bromine gas and bromine dissolved in a solvent (Bromine absorbs maximum at wavelength between 400 and 500nm). Explain the differences.

Explanation / Answer

1. The absorption maxima observed is due to n--->pi* transition. If a solvent is added to it, the maxima will shift towards lower wavelength. this is due to the fact that lone pair of electron on bromine can interact strongly with solvent molecule and n orbital is stabilize. Whereas pi* orbital is much less afeefected. As a result the transition energy is increased and wavelength shifts towards a shorted wavelength.

2. Sovent added will show peak in the electronic sprectrum. For example if acetone is used as solvent a peak will be obsered at 271 nm along with usual peak of bromine.

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