What is the IUPAC name of the compound shown below? (1R, 4S)-1, 4- dichloro -1 -
ID: 1048500 • Letter: W
Question
What is the IUPAC name of the compound shown below? (1R, 4S)-1, 4- dichloro -1 - ethyl - 4 - methylcyclopentane (1S, 3R) -1, 3 - dichloro - 3 - ethyl -1 - methylcyclopentane (1R, 3S) -1, 3- dichloro -1 - methyl - 3 - ethylcyclopentane (1R, 3S)-1, 3-dichloro - 1 - ethyl -3 -methylcyclopentane (1S, 4S)-1, 3-dichloro-1-ethyl-3-methylcyclopentane Arrange the following alkyl halides in order of increasing boiling point: CH_3CH_2Br, CH_3CH_2CH_2Br, (CH_3)_2CHBr, CH_3CH_2F. Name the haloalkane shown. Be sure to include the appropriate R or S description if needed. Which of the following compounds is the most nucleophile? CH_3CO_2H BF_3 CH_3OH H_2O CH_3SH Which of the following solvents could be described as polar and protic? 18-crown-6 dimethylformamide ethanol acetone acetonitrile Which of the following compounds will undergo an S_N2 reaction most readily? (CH_3)_2CHCH_2CH_2CH_2Cl (CH_3)_2CHl (CH_3)_2CHCH_2CH_2CH_2l (CH_3)_3CCH_2l (CH_3)_3CClExplanation / Answer
6) D
7) The boiling point of an organic molecule depends on the factors i) molecular weight ii) branching iii) secondary forces of attaraction
As the molecular weight increases, boiling point also increases.
More branching, less is the boiling point, which makes the molecule more symmetric ,less surface area, less vander waals' attractions. thus less boiling point.
H-bonding increases the boiling point.
Thus among the given molecules the order isCH3CH2F < CH3CH2Br < (CH3)2ChBr < CH3CH2CH2Br
8) 1-chloro-3,3-dimethylcyclohexane
9) Most nucleophilic is CH3SH.
Acetic acid is not nucelophilic as the oxygens are ivolved in resonance
BF3 is an electrophile , it is delectron deficient molecule.
In CH3Oh, H2O and CH3SH, first two have oxygen as the electron donating atom which is more electronegative than the S in third which is donor atom.Thus S compounds are better nucleophiles than oxygen donor nucleophiles.
10) Polar protic solvents are the ones which have a hydrogen atom on the more electronegative F or O or N atom. and are capable of forming H- bonds.
Among the given ones only CH3Oh has such proton and also polar. So it is polarprotic solvent.
Others, crown ethers, DMf, acetonitrile though are polar but not protic solvents. They are known as polar 'aprotic' solvents.
Acetone is less polar aprotic solvents.
11) For SN1 reaction to take readily , steric hindrance should be less.
the compound with less steric factor are A) and C) , but C) has I which is good leaving group.
Thus C) is the correct option.
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