The pressure changes from 760 tore to 202 kPa, and the temperature changes from

Question

The pressure changes from 760 tore to 202 kPa, and the temperature changes from 37 degree C to 155 K. The volume increases by a factor of 2. The volume increases by a factor of 4. The volume decreases by a factor of 2. The volume decreases by a factor of 4. The volume remains the same. The temperature changes from 305 K to 32 degree C, and the pressure changes from 2 atm to 101 kPa. The volume increases by a factor of 2. The volume increases by a factor of 4. The volume decreases by a factor of 2. The volume decreases by a factor of 4. The volume remains the same.

Explanation / Answer

a)

Apply:

P1V1/T1 = P2V2/T2

760 torr = 101.3 kPa

P2 = 202

T1 = 37°C = 37+273 = 310 K

T2 = 155

so:

P1V1/T1 = P2V2/T2

V2/V1 = P1/P2*T2/T1

V2/V1 = 202/101.3*155/310

V2/V1 =0.99703

volume remains almos the same

b)

dT =

T1 = 305 K

T2 = 32°C = 32+273 = 305 K

P1 = 2 atm

P2 = 1 atm

then..

P1V1 = P2V2

2V1 = V2

then

V2 = twice the initial volume... so choose A

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