1. An excess of sodium sulfate, Na SO, was added to a 1.000-L sample st pollu (N
ID: 1046202 • Letter: 1
Question
1. An excess of sodium sulfate, Na SO, was added to a 1.000-L sample st pollu (Na,So.faq)JPb(NO(a) 2NaNOae).Pbso4s) PN nRT mass of lead (1) sulfate, PbSO,(MM-303.26 g/moD, that precipitated was 208.38 mg. Determine the er. The 2. A 0.239 g sample of a gas in a 300-mL flask exerts re of 0.67 atm at 14 °C. What is the gas? (4 pt) A)A (b) ? (c) Kr (d) Xe (e) 02 Ib3 22, wsu 3. According to the equation 6 SnOz(s) + 2H2 (g) ? Sn (s) + 2H20(1) What volume of hydrogen, measured at STP, is required to react with 10.00g of SnO2 (MM-150.71 g/mol),? (4 pt) 30.41 . The specific heats of several metals are given in the below. If the same number of loules were applied o the same mass of each metal, which metal would show the lowest temperature change? (3 pt) (d) Hg (e) Fe 0 (a) Al b)u(c) Cu Specific Heat, J/g Al 0.900; Au 0.129; Cu 0.385; Hg0.139; Fe 0.450Explanation / Answer
Ans 1 :
The number of moles of lead sulfate precipitated = (208.88 x 10-3 )/ 303.26 = 0.689 x 10-3 mol
The molar mass of lead = 207.2 g/mol
So the mass of lead in sample = 0.689 x 10-3 x 207.2
= 142.7 mg
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