Mangoneset) comple Spin A Re analogue to complex I is known. Below is the crysta

Question

Mangoneset) comple Spin A Re analogue to complex I is known. Below is the crystal structure determined by X diffrac 4 A Re a asigning the point groups in discussion theme number 2, you were instructed to ignore t phe on ( atoms omitted for clarity) and the FTIR spectrum (solid state). When nyl and phenoxy groups of the phosphine ligands and assume idealized geometry. p structure it is clear the structure is not idealized. Based on the structure and the crystal is the assumption valid? Explain Re1 C302 C1 85 494.79m-1 75 1218 1435.57am- 1007 26cm-1 6892 2028 920.88cm-1 88 69cm-1 3500300025002000 1500 1000 650

Explanation / Answer

Answer:

Aromatic C=C BENDING = 1700-1500 cm-1 so 1435-1457cm-1

Cyclic 6- membered -1715

C-O = 1050-1150

=C-H= 675 -1000 (BENDING)

C-Br = 500-600

ACID C-O =1210- 1000

ALKANE C-H BENDING =1350-1480

From FTIR frequency data gives an idea about the structurebecause it gives the rough idea about the molecules or groupspresent in the structure sch that phenyl and phenoxide groupindecates the aromatic c=c frequency .

and C-O straching frequency.and sharp peak for phosphinegroup present in pph3 - 2280-2440 cm-1.

therefore it is proved that this is the correct structure forthis complex.

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.