2. Consider the following chemical reaction: 3 12(s 6OH- (aq) 5(a) O(aq)+3 H2OO
ID: 1043465 • Letter: 2
Question
2. Consider the following chemical reaction: 3 12(s 6OH- (aq) 5(a) O(aq)+3 H2OO a) Calculate ?G. for this reaction as written above at 25°C. Is this reaction spontaneous or non- spontaneous at standard states at 25°C? (You will also need. AG"f (l_ (aq))--51.6 kJ/mol and ?Gof (10,-(aq))--1280 kJ/mol. Depending on the edition of the textbook you are using, the AGf of(a) given in Chang may be printed incorrectly-you should use the value given here.) b) Calculate the equilibrium constant K for this reaction at 25°C c Given [H1-0.015 M and [IO1 0010 M, determine the pH required for this reaction to be at equilibrium at 25°C.Explanation / Answer
(a)
deltaG0 = 5 * deltaG0f(I-) + deltaG0f(IO3-) + 3 * deltaG0f(H2O) - 3 * deltaG0f(I2) - 6 * deltaG0f(OH-)
= 5 ( - 51.6 ) + ( - 128.0 ) + 3 (-118.1) - 3(0) - 6(157.3)
= 203.5 kJ
(b)
deltaG0f = - R T lnK
203.5 = - 0.008314 * 298.15 * lnK
lnK = - 82.1
K = 2.21 * 10-36
(c)
K = [I-]5[IO3-] / [OH-]6
2.21 * 10-36 = (0.015)5(0.010) / [OH-]6
[OH-]6 = 3.44 * 1024
[OH-] = 1.23 * 104
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