An unknown IR spectra is given. Boiling point (Liquid) was aprox. = 150-152 Celc
ID: 1042510 • Letter: A
Question
An unknown IR spectra is given. Boiling point (Liquid) was aprox. = 150-152 Celcius. The unknown is either a Ketone, Aldehyde, or Alcohol.
A) Lable the major IR peaks on the IR provided.
B) Give a guess on which functional group is in this unknown based off of IR (Ketone, Aldehyde, Alcohol)
C) Give 5 possible guesses on the product based on Melting Point, Function Group, and IR spectra.
Major Peaks: 3370.80, 3315.77, 2927.55, 2854.22, 1450.40, 1363.10, 1065.45, 1025.33, 966.71 (As seen below)
%Transmittance 4000 & #848 & 3 a & S8 3500 3500 3370.80 3315.77 3000 2927.55 2854.22 2500 Wavenumbers (cm-1) 2000 1500 1450.40 1363.10 1065.45 1025.33 1000 966.71 500Explanation / Answer
It is confirmed that neither aldehyde nor ketone are present due to absence of characteristic IR peak around 1700cm-1. It is an alcohol due to presence of broad peak around 3300.
The peak at 2927 and 2854 are due to assymetric and symmetric C-H stretch in saturated alkanes while peak at 1450 and 1363 are due to CH2 and CH3 bending vibrations. Strong peak at 1065 is due to C-O stretch.
On comparing your boiling point with literature reported boiling point for alcohol, it seems your liquid is most likely among the following: hexanol or cyclohexanol
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