3. In the Haber process, nitrogen and hydrogen gases combine to form ammonia gas

Question

3. In the Haber process, nitrogen and hydrogen gases combine to form ammonia gas. Answer the questions below in reference to this reaction, using information from Table 1 as needed. Table 1. Equilibrium Constants for the Haber Process Temperature (°C) 200 K, 34 x 10 1.64 x 10 45 x 10-s 25 x 10 500 Write a reaction equation for this equilibrium reaction, be sure to include physical states and to balance the equation. Write an equilibrium expression that corresponds to Kp for the reaction (use partial pressures, not molarity). a. b. Calculate the partial pressure of ammonia at equilibrium at 600°C, when the partial pressure of hydrogen is 25 atm and nitrogen is 15 atm. What is the total pressure of the gas mixture at equilibrium at this temperature? c. At which temperature is the reactant to product ratio nearly equal? Which temperature is least favorable to product formation? d. Calculate Kc for this equilibrium at 573 K. e. For the system at equilibrium (at room temperature) in a flask, apply Le Chatelier's principle to determine the direction of shift in each of the situations described below (please use product/reactant terminology rather than right/left thanks) i. Hydrogen gas is removed from the system ii Ammonia is injected into the flask ii. The flask is placed in an ice water bath iv. Propose at least one way in which this equilibrium could be manipulated (without adding more reactants) to increase the yield ammonia product. Explain your reasoning. Use complete sentences. v. At 400°C, initial pressures are 105 atm NHs, 35 atm N2, 495 atm H2 vi. At 573 K, initial concentrations at 0.75 M f. Using the information in Table 1, explain how you can tell whether this reaction is exothermic or endothermic. No calculations are required to answer this question.

Explanation / Answer

a. N2 (g) + 3H2 (g) = 2NH3 (g)

Kp=pNH3/pN21/2XpH2^3/2

b. pNH3 = Kp*pN2^1/2xpH2^3/2 = 1.0893X10^-3

c. 400-500C and 200C

d. Kp = Kc (RT)^delta(n), so Kc = Kp/(RT)^delta (n), in this case delta(n) = 2-(3+1) = -2, Kc = 1.191X10^30

e. i. Reation will move to left; ii. Reaction will move to left; iii. reaction will move to right; iv. increase the pressure to 200 atm;

f. It is endo thermic reaction as heat is absorbed in the reaction

Related Questions

Navigate

• Browse (All)
• Browse 3
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.