(e) react with starch as the endpoint is approached. n Experiment M, the activat

Question

(e) react with starch as the endpoint is approached. n Experiment M, the activation energy can be obtained using the equation k Ae-Ea/RT where R is the gas law constant, T is the temperature in Kelvin, and k is the rate constant. The following graph represents your results. On it, a is ?1ogk, and bis ?(1/T). The numerical value (in appropriate units) for a is-0.63 and b s 2.52 x 10-4. What is your Ea? log k 1/T (K) (a) 479 J.mol-1 (b) -479 J.mol-1 (c) -47.9 kJ.mol-1 (d) 47.9 kJ.mol-1 (e) 479 kJ.mol-1

Explanation / Answer

k = A exp (-Ea/RT)

Take natural log on both sides

Ln k = (-Ea/R) *(1/T) + ln A

Conversion of ln to log

Then

Slope = - (Ea/R) / 2.303

a/b = ( - Ea/R) / 2.303

(-0.63/2.52*10^-4) * 8.314 x 2.303 = - Ea

Ea = 47867 J/mol = 47.867 kJ/mol

Ea = 47.9 kJ/mol

Option D is the correct answer

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