Map University Science Books presented by Sapling Learning General Chemistry 4th

Question

Map University Science Books presented by Sapling Learning General Chemistry 4th Edition | Compound | N, (kl/moll Use the data given here to calculate the values of AGrxn at 25 "C for the reaction described by the equation +387.7 +647.4 +402.0 Number kJ/ mol If AHrn and AS rxn are both negative values, what drives the spontaneous reaction and in what direction at standard conditions? The spontaneous reaction is O enthalpy-driven to the right. O entropy-driven to the right. O enthalpy-driven to the left. O entropy-driven to the left.

Explanation / Answer

Given:
Gof(A) = 387.7 KJ/mol
Gof(B) = 647.7 KJ/mol
Gof(C) = 402.0 KJ/mol

Balanced chemical equation is:
A + B ---> C

?Go rxn = 1*Gof(C) - 1*Gof( A) - 1*Gof(B)
?Go rxn = 1*(402.0) - 1*(387.7) - 1*(647.7)
?Go rxn = -633.4 KJ/mol
Answer: -633.4 KJ/mol

Since ?Go rxn is negative, forward reaction is spontaneous
So, it is driven to the right
Since
?Go = ?Ho - T*?So
?Go is negative because of negative ?Ho
Answer: enthalpy driven to the rihght

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