Map Sapling Learning macmllan learning by varying the compo Trial 2 0.0 mL (aq)

Question

Map Sapling Learning macmllan learning by varying the compo Trial 2 0.0 mL (aq) measuring resulting rates of reaction. Reactant Solution A 10.0 mL (aq) Reactant Time to complete 10 seconds Trial 1 5.0 mL S203(a) 5.0 mL S203(aq) .0 mL starch (aq) 1.0 mL starch (aq) Solution B 10.0 mL S,0 (aq) 5.0 m L Ss2 (a) 20 seconds reaction How do trial 1 and 2 in the above table differ? O Trial 1 has twice as much F as Trial 2 O Trial 2 has twice as much S,0s as Trial 1 Trial 2 has half as much S2Os as Trial 1 Trial 1 has half as much starch as Trial 2

Explanation / Answer

From first part : As the amount of S2O8^2- goes down, the reacion rate decreases (run time increases from 10 s for trial 1 to 20 s for trial 2).

Second part : So the concentration of S2^O8^2- affects the rate of reaction directly and thus it must appear in the rate determining step of the reaction. Rate determining step is the slow step in the reaction mechanism.

By looking at the 4 options, Mechanism 2 : has S2O8^2- appearing in the slow step directly and forms complex which decomposes in the fast step.

Thus, the mechanim which supports results in First part would be,

Proposed mechanims 2

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