r\'0 at 8 AM CDT is alowed, with a one time 10% penalty to submitted score. Use

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r'0 at 8 AM CDT is alowed, with a one time 10% penalty to submitted score. Use the References to access Important values if meeded for this question In the laboratory a student uses a "coffee cup" calorimeter to determine the specific heat of a metal. She heats 19.5 grams of magnesium to 98.06°C and then drops it into a cup containing 78.1 grams of water at 22.91°C. She measures the final temperature to be 27.05 C Assuming that all of the heat is transferred to the water, she calculates the specific heat of magnesium to be Submit. Answer Coffee Cup Calormetry. Heat of Solultion E This is group attompt 1 of 5 Autosaved at 5:02 PM MacBook Air 20 1 4 0

Explanation / Answer

Specific Heat of water Cw = 4.186 J/g-oC

Mass of water mw = 78.1g

Mass of magnesium mMg= 19.5g

Change in temperature of magnesium deltaTMg = 98.06 - 27.05

= 71.01oC

Change in temperature of water

deltaTw = 27.05 - 22.91

= 4.14oC

Now,

Heat lost by magnesium = Heat gained by water

mMgCMgdeltaTMg = mwCwdeltaTw

19.5 * CMg * 71.01 = 78.1 * 4.186 * 4.14

CMg = 0.9774 J/g-oC

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