Please show all steps and explain clearly. Thank you! The solubility of a specif

Question

Please show all steps and explain clearly. Thank you!

The solubility of a specific penetrant molecule in a solid polymeric membrane has been measured. The species has a molecular weight of 75. The experimental data obtained at 30°C by exposing a piece of polymeric membrane to the pure vapor of this solute. The solute-free membrane weight was 0.0572 g. The weight gain was measured when the system reached to an equilibrium (no further weight gain). At 30 °C the vapor pressure of this solute is 76 mmHg. The measured net weight gain was 4.76X103 g. The density of the polymeric membrane, solute free, is 0.9 g/cm3 Find the solubility coefficient in terms of gmol/cm3 atm (S) from this data. Membrane Vapor Liquid

Explanation / Answer

The solubility coefficient of a gas in a membrane is the ratio between its solubility C in the membrane and its pressure P

S = C /P

S is the solubility coefficient

C is the concentration of the gas dissolved in the polymer

since the weight gain after exposing the membrane to the solute vapour is 4.76 * 10-3g. this is the concentration of the gas absorbed.

No of moles = mass in g / molecular mass

= 4.76 * 10-3 / 75

= 0.063 * 10-3 moles of gas

applying in our equation

S = C /P

76 mm/hg is 0.1 atm

= 0.063 * 10-3 / 0.1

= 0.63 * 10-3 gmol/ cm3 atm

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