nitrate, LiNO3, t0 1.00 of pure water. This solution &. A solution is prepared b
ID: 1038035 • Letter: N
Question
nitrate, LiNO3, t0 1.00 of pure water. This solution &. A solution is prepared by adding 0.10 mol of lithi will have a pH: A. 7 that in a solution containing 9. The solubility of AgCI (Ksp 1.77x 10-10y in pare wiater will NaCl and that in a solution containing AgNO3, respectively. (Hint; no calculation needed!) C. the same as, the same as A. higher than, higher than D. higher than, lower than B. lower than, lower than E. lower than, higher than 10. For the equilibrium: A [Ag(S203)213-(aq) + Briaq) Kf-25. Some solid AgBr is gBr(s) + 2S2O3Taq) added to a solution containing boh o 1.0 and NaBr. At equilibrium some solid AgB remains, Brl- M, and [S2032]-0.010 MM. The equilibrium concentration in moles/L of [Ag(s203)2)3- is, therefore: Hint: you do not need to know or calculate the initial concentrations of Na28203 and NaBe) C.5.0x 10-4 E. 2.5 x 10-5 B. 2.5 x 10-3 D. 5.0 10-5 A. 625 11. The only one of the following compounds that would give a solution with a plH> 7 is A. HCI04B. KCN C. CO2 D. NaCI04 E. NH4CIO4 12, HF has a pKa-3.15. The pH ofabuffer containing 0.30 M HF and 0.30 ??? is: A. 1.00 B. 7.1 x 10-4 c. 3.15 D. 7.00 1025, For a solution initially containing 0.002 M CusO4 (Ca(CN)4- has Kf 10 ediate Cu2+ complexes with one, two, or three CN, pH can be ignored, and you dont 13. Cu2teg)+4CN and 0.3 MKCN the concentration in moles/IL of [Cu(CN412- at equilibrium is: (Hint: You don'i need to consider the interme need to solve a quadratic) B. 0.3 C. I x 10-25 D 3 10-27 E. 5 x 10-25 A. 0.002 14. PbCl2 is a slightly soluble salt with Ksp- 1.17 x 10-5. The grams of solid NaCI (FW-58.44) that must be added to 1.0L of a solution initially containing 0.0010 MPb(NO3)2 to the point that PbCl2 just begins to precipitate (ie., at the point where 0 - Ksp) is: (Assume no change in volume of the solution when the solid NaCl is added A, 0.0020 B, 0.30 C.63 15. The molar solubility AgCl (Ksp = 1.7 x 10-10) in pure water is closest to: A 0.0020 ?.0.30r 5 D. 1.7 x 10-10 C. 1.3 x 10Explanation / Answer
8) option C
the pH of LiNO3 solution which is a salt of strong acid HNO3 and strong base LiOH is equal to 7 as it is neutral.
9) option A
the solubility of AgCl in ure water is HIGHER than those in solutions containing common ion (Nacl or AgNO3) due to common ion effect.
10) option B
Kf = [Br-] [AgS2O3-3] /[S2O3-2]2
Substituting the given values
25 = 1.0 x [AgS2O3-3] / [1.0x10-2]2
Thus [AgS2O3-3] = 2.5x 10-4
11) option B
Only KCN is a salt of strong base KOH and weak acid HCN, which is basic in solution due to anionic hydrolysis.
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