Part A Calculate the mass percent (m/m) of a solution prepared by dissolving 57.

Question

Part A

Calculate the mass percent (m/m) of a solution prepared by dissolving 57.09 g of NaCl in 176.6 g of H2O.

Express your answer to four significant figures.

Part B

Vinegar is a solution of acetic acid in water. If a 225 mL bottle of distilled vinegar contains 17.9 mL of acetic acid, what is the volume percent (v/v) of the solution?

Express your answer to three significant figures.

Part C

Calculate the mass/volume percent (m/v) of 14.0 g NaCl in 70.0 mL of solution.

Part D

Calculate the molarity (M) of 151.8 g of H2SO4 in 1.020 L of solution.

Explanation / Answer

A)

m/m % = mass of solute * 100 / mass of solution

= 57.09*100 / (57.09+176.6)

= 24.43 %

Answer: 24.43 %

B)

v/v% = volume of acetic acid * 100 / volume of solution

= 17.9*100 / 225

= 7.96 %

Answer: 7.96 %

C)

m/v % = mass of solute * 100 / volume of solution

= 14.0*100 / 70.0

= 20.0 %

Answer: 20.0 %

D)

Molar mass of H2SO4,

MM = 2*MM(H) + 1*MM(S) + 4*MM(O)

= 2*1.008 + 1*32.07 + 4*16.0

= 98.086 g/mol

mass(H2SO4)= 151.8 g

use:

number of mol of H2SO4,

n = mass of H2SO4/molar mass of H2SO4

=(151.8 g)/(98.086 g/mol)

= 1.548 mol

volume , V = 1.020 L

use:

Molarity,

M = number of mol / volume in L

= 1.548/1.02

= 1.517 M

Answer: 1.517 M

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