Reaction 1 Reaction 2 Reaction 3 1. Initial temperature (C) 2. Maximum Final Tem

ID: 1037587 • Letter: R

Question

Reaction 1 Reaction 2 Reaction 3 1. Initial temperature (C) 2. Maximum Final Temperature (°C) 3. Temperature Change, AT (C) 33.9? 4. Volume of Acid (mL) 5. Volume of Base (mL) Instructors Approval of Graph Volume of Final Mixture (mL) Mass of final mixture (assume all solutions have a density of 1.03 gmL) Specific Heat of Mixture Heat Evolved (J) 4.18 Moles of acid (mol) AHn (kJ/mol of acid) AH (kJ/mol) from Hess' Law 1. Calculate the amount of heat energy. q produced in each reaction. Use 1.03 g/mL for the density ofall solutions. Use the specific heat of water, 4.18 JOg.°C), for all solutions.

Explanation / Answer

Reaction 1

Reaction 2

Reaction 3

1) Initial temperature (°C)

21.5

21.0

21.1

2) Maximum final temperature (°C)

33.4

32.2

32.5

3) Temperature change, ?T (°C)

(33.4 – 21.5) = 11.9

(32.2 – 21.0) = 11.2

(32.5 – 21.1) = 11.4

4) Volume of acid (mL)

5) Volume of base (mL)

Volume of final mixture (mL)

100

Mass of final mixture (assume all solutions have a density of 1.03 g/mL)

Mass of solution = (volume of final mixture)*(density of solution)

(100 mL)*(1.03 g/mL) = 103 g

Specific heat of mixture

4.18 J/g.°C

Heat evolved (J)

= (mass of solution)*(specific heat of solution)*?T

(103 g)*(4.18 J/g.°C)*(11.9°C) = 5123.426 J

(103 g)*(4.18 J/g.°C)*(11.2°C) = 4822.048 J

(103 g)*(4.18 J/g.°C)*(11.4°C) = 4908.156 J

Moles of acid (mol)

Need to know the molarity of the acid used to calculate the moles of acid.

?Hn (kJ/mol)

Need to find out the moles of acid from the above step.

?Hn (kJ/mol) from Hess’ law