9. Assign oxidation states to each atom in the chemical reaction below. Indicate

Question

9. Assign oxidation states to each atom in the chemical reaction below. Indicate the element that is oxidized and the element that is reduced. Indicate the oxidizing agent and the reducing agent. (10 pts) CH4 (s) 2 02 (s) -CO2 (3) 2 H20 (s) 10. Google is conducting a project to float balloons to connect people in remote areas of the world to the internet. You are designing a balloon prototype that will be inflated to 24.8 L at a pressure of 748 mm Hg and a temperature of 28.0° C. The balloon will be floated into the atmosphere to an altitude where the pressure is 385 mm Hg and the temperature is 15.0° C. Assuming the balloon can freely expand and contract and the gas contents a this altitude? re kept constant, what is the volume of the balloon at

Explanation / Answer

9)

oxidation = increase in oxidation number

reduction = decrease in oxidation number

oxidizing agent = substance which oxidizes other species by undergoing self reduction

reducing agent = substance which reduces other species by undergoing self oxidation

Given reaction is

CH4 + 2O2 -------------------> CO2 + 2H2O

a) Oxidation number of C in CH4:

We know that oxidation number of H is +1.

Hence, C + 4(+1) = 0

C = -4

Therefore,

Oxidation number of C in CH4 = -4

b) Oxidation number of O in O2:

We know that Oxidation number of any element in uncombined state is 0.

Therefore,

Oxidation number of O in O2 = 0

c) Oxidation number of C in CO2:

We know that oxidation number of O is -2.

Hence, C + 2(-2) = 0

C = +4

Therefore,

Oxidation number of C in CO2 = +4

d) Oxidation number of O in H2O:

We know that oxidation number of H is +1.

Hence, 2(+1) + O = 0

O = -2

Therefore,

Oxidation number of O in H2O = -2

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Therefore,

oxidation number of Carbon (C) increased from -4 (CH4) to +4 (CO2)

oxidation number of Oxygen (O) decreased from 0 (O2) to -2 (H2O)

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Therefore,

oxidised element = CH4

reduced element = O2

oxidizing agent = O2

reducing agent = CH4

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