1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. Consider the following reaction where Kc 77.5

Question

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Consider the following reaction where Kc 77.5 at 600 K. COgCl2@CoCh(g A reaction mixture was found to contain 1.95x10-2 moles of CO(g). 4.15x10-2 moles of Cl2) and 9.94x102 moles of cocl2(g), in a 1.00 liter container. Is the reaction at equilibrium? If not, what direction must it run in order to reach equilibrium? The reaction quotient, Qc equals The reaction A. must run in the forward direction to reach equilibrium. B. must run in the reverse direction to reach equilibrium. C. is at equilibrium.

Explanation / Answer

Question 1 :

answer: we have

Kc = 77.5
[CO] = 1.95 x 10^-2 mole/L
[Cl2] = 4.15 x 10^-2 mole/L
[COCl2] = 9.94 x 10^-2 mole/L
and
For the reaction
CO (g) + Cl2 (g) <-----------------> COCl2 (g)
we have
Q = [COCl2] /[CO]*[Cl2]
or
Q = 9.94 x 10^-2 mole/L / (1.95 x 10^-2 mole/L x 4.15 x 10^-2 mole/L)
or
Q = 1.2283 x 10^2
or
Q = 122.83
thus
Q > Kc
therefore
reaction will :
B. must run in reverse direction to reach equilibrium.

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