Question 13 of 32 Map coa General Chemistry 4th Edition University Science Books
ID: 1036062 • Letter: Q
Question
Question 13 of 32 Map coa General Chemistry 4th Edition University Science Books presented by Sapling Leaming Glucose, Ce, is used as an energy source by the human body. The overall reaction in the body is described by the equation Calculate the number of grams of oxygen required to convert 28.0 g of glucose to CO2 and H2O Number 26.13 Also compute the number of grams of CO2 produced Number 77.62 g CO, There is a hint available! View the hint by clicking on the bottom divider bar. Click on the divider bar again to hide the hint Close Previous Give Up & View SolutionCheck Answer NextExit HintExplanation / Answer
1 mole of glucose = 72 + 12 + 96 = 180 g
180 g of the Glucose requires 6x32 g = 192 g O2 ( 6 moles of Oxygen)
28 g of Glucose requires 28 g x 192 g / 180 g = 29.86 g O2
180 g of Glucose produces 6x44 = 264 g CO2 ( 6 moles of CO2)
28 g of glucose produces 28 x 264 / 180 = 41.07 g CO2
** If you like the answer, it deserves your upvote/thumbs up :)
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.