Question 13 Part A Constants | Periodic Table Use the relationship between bond

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Question 13 Part A Constants | Periodic Table Use the relationship between bond lengths and single covalent radii of atoms: "the length of the covalent bond between two atoms can be approximated as the sum of the covalent radi of the two atoms" together with appropriate data from the table to estimate these single-bond lengths. Express the answer in pm to three significant figures TABLE 10.2 Some Average Bond Lengths Bond Bond Length, pm 145 123 109.8 Bond pim Bond Length, pm Bond Length, pm Bond H-H H-C H-N 100 C-C 154 C-C 134 C-C 120 C-N 147 C-N 128 ? N 116 C-O 143 C=O 120 C-CI 178 N-N Submit RequestAnswer 74.14 110 ? Part B 97 132 N-O 136 N-O 120 145 121 143 Cl-CI 199 Br-r 228 266 O-Cl H-F H-CI127.4 H-Br 141. H-I 91.7 Express the answer in pm to three significant figures. F-F 160.9 pim aMost values (C-H, N-H, C H, and so on) are averaged over a number of species containing the indicated bond and may vary by a few picometers. Where a diatomic molecule exists, the value given is the actual bond length in that molecule (H2, N2, HF, and so on) and is known more precisely. Submit Request Answer Part C You may want to reference (Page) Section 10.1 while completing this problem C-F Express the answer in pm to three significant figures pim Submit RequestAnswer ? Part D C-Br Express the answer in pm to three significant figures. pim

Explanation / Answer

The bond lengths of these bonds can be determined using the average bond lengths of the covalent bonds mentioned in the table in picture.

So here :

Part A :

I-I =266

= 266 / 2 = 133 pm

Cl-Cl =199

= 199 / 2 = 99.5 pm

So then , I-Cl = 133 + 99.5

= 232 pm

Part B :

O-O = 145

= 145 /2 = 72.5

So O-Cl = 72.5 + 99.5

= 172pm

Part C :

C-C = 154 pm

= 154 /2 = 77pm

F-F = 143 pm

= 143 / 2 = 71.5 pm

So then , C-F = 77 + 71.5

= 148 pm

Part D :

C-C = 154 pm

= 154 / 2 = 77 pm

Br-Br = 228 pm

= 228 /2 = 114 pm

So C-Br = 77 + 114

= 191 pm

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