1.) Suppose you have 2 moles of NaCl. You dissolve it in 500 mL of water. What i

Question

1.) Suppose you have 2 moles of NaCl. You dissolve it in 500 mL of water. What is the molarity of this solution?

2.) From the solution you just made in Question 1, you transfer 2 mL into 4 seperate test tubes each. How many moles of NaCl are now in each test tube? How many grams of NaCl are in each test tube?

3.) Suppose you want to neutralize (titrate) 0.5 L of 2M acetic acid CH3COOH. You have a solution of 6M NaOH. How many liters of 6M NaOH would you need to add?

4.) If the initial burrette reading is 0.12 mL and you add 39.25 mL of 6.25M NaOH, how many moles of NaOH did you add?

5.) Under the Bronsted-Lowery definition, acids are defined as substances that release protons when they react wheras bases react by attracting protons. Use this definition and the following reaction to answer Questions A and B.

2 NaOH + H2C2O4 ----> Na2C2O4 + 2 H2O

a.) Does H2C2O4 react as an acid or base? Justify your answer.

b.) What part of H2O comes from NaOH? Based on this, how do we know NaOH reacts as a base?

Explanation / Answer

1) molarity is defined as moles of solute present in one liter of solution and expressed as (moles of solute/ volume of solution in liter)

Given that, volume =500ml =0.5L

Thus, molarity=2moles/ 0.5L= 4M

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