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Sorry for posting all the information. I am trying to find out how to find the V

ID: 1035478 • Letter: S

Question

Sorry for posting all the information. I am trying to find out how to find the Volume: CO2 collected in this experiment after the data was gathered.

Complete the following table with your experimental data and calculations. You must show your calculations on the next page to receive full credit. (40 pts) Trisl 1 -Crushed Tablet Tria 2-Lab Grade Standard Units Collected Data o. 1 00q o. 080 99 Mass: gelatin capsule Mass: whole Alka-Seltzer tablet Mass: capsuleAlka-Seltzer sample Temperature in classroom ("C) Pressure in the room (atm) Volume of HCI added (mL) Mass of side-arm with HCl and capsule | O. I 94 3 g O. 1540 g 24.0"c 24.0°c| .0o atm oC 66.1347 before reaction l 68.7143 Initial Volume of H-o in buret (ml) 50 L 50 Final Volume of H:O in buret (mL) ! Cg.70SL Seltzer n capui r la0.043 Mass of ction-arm with Ha and capsule | ?6. L6 after reaction (g)* g Calculated Values Mass of Alka-Seltzer in capsule or lab grade standard used. Volume: CO2 collected 0.0740 Moles: CO2 (using Ideal Gas Equation) Moles NaHCOs reacted Mass: NaHCOs reacted Mass: NaHCOs in tablet or standard (g) % NaHCOs in tablet or standard mol mol Mass of CO2 collected ("Use values from above to calculate lost mass) Density of CO: (using moles collected and mass calculated above) Average Density of CO

Explanation / Answer

From the stoichiometric equation we can say

HCO3- + H+ _______} H2O+ CO2

61 grams of bicarbonate is producing 1 mole of carbon dioxide

Then 0.0943 grams of bicarbonate sample produce how many miles?

= 0.00943/61

= 0.00154 moles .

At STP 1 mole of carbon dioxide occupies 22.4 L

Then 0.00154 occupies how much volume?

0.00154×22.4

= 0.0346 L

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