Calculate the mass of copper(II) sulfate pentahydrate (CuSO4?5H2O) that would be

Question

Calculate the mass of copper(II) sulfate pentahydrate (CuSO4?5H2O) that would be necessary to yield the same conductivity as a solution that contains 1.0 g of ammonium chloride (NH4Cl). Show all your work and units.
Calculate the mass of copper(II) sulfate pentahydrate (CuSO4?5H2O) that would be necessary to yield the same conductivity as a solution that contains 1.0 g of ammonium chloride (NH4Cl). Show all your work and units.
Calculate the mass of copper(II) sulfate pentahydrate (CuSO4?5H2O) that would be necessary to yield the same conductivity as a solution that contains 1.0 g of ammonium chloride (NH4Cl). Show all your work and units.

Explanation / Answer

Answer:

Molar conductivity depends on the number of moles Ions present in solution.

Equimolar solutions of BINARY salts will have same molar conductivity.

Let us first calculate # of moles of NH4Cl.

Mass of NH4Cl in solution = 1.0 g, Molar mass of NH4Cl = 53.49 g/mol

Moles of NH4Cl = Given mass in grams / Molar mass = 1.0 / 53.49 = 0.0187 moles.

It means 0.0187 moles of  copper(II) sulfate pentahydrate (CuSO4?5H2O) will give same molar conductivity as 0.0187 moles of NH4Cl gives.

Mass of  copper(II) sulfate pentahydrate (CuSO4?5H2O) = # of Moles * Molar mass = 0.0187*159.61

Mass of  copper(II) sulfate pentahydrate (CuSO4?5H2O) = 2.984 g

2.984 g of  copper(II) sulfate pentahydrate (CuSO4?5H2O) dissolved in same volume as NH4Cl will have same conductivity.

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