ege-CHEM 1212K-Spring18- MAJDIActivities and Due Dates HW 1:2 47.7/100 3/27/2018

Question

ege-CHEM 1212K-Spring18- MAJDIActivities and Due Dates HW 1:2 47.7/100 3/27/2018 12:55 PM Print Calculator Periodic Table Gra of 29 Map d If you were going to graphically determine the activation energy of this reaction, what points would you plot? Consider this reaction data: A ? products Number Number T (K) k(s) 225 0.392 625 10.773 point 1: To avoid rounding errors, use at least three significant figures in all values Number point 2:n Determine the rise, run, and slope of the line formed by these points. rise run slope Number Number What is the activation energy of this reaction? J/ mol Previous& Give Up & View Solution Check Answer xtExit Hint

Explanation / Answer

k=Aexp(-Ea/RT) where k is rate constant, Ea is activation energy, R is universal gas constant and T is temperature.

logk= logA - Ea/RT

So in order to determine Ea, the plot should be of logk vs 1/T.

Point 1: x=0.00444(K-1), y= -0.4067

Point 2:x=0.0016(K-1), y= -0.1118

Rise = y2-y1 = 0.2949

Run = x2-x1 = -0.0028

Slope= 105.316 mol-1K-1

The slope is negative.

Activation energy Ea= 0.875 kJ

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