eexample data below: Ba(OH)2 11.89 2.11 7.762 103 3.881 10-3 3.881 103 2.339 10-

Question

eexample data below: Ba(OH)2 11.89 2.11 7.762 103 3.881 10-3 3.881 103 2.339 10-7 PH ??? Bs(OH)2 in BsCl2 1.45 2.55 2.818 10 Bs21 Molar Solublility of Bs(OH)2 Ksp for Bs(OH)2 1.409-10-3 1.409 103 1.119 10- How would NOT utilizing the additional Bs2t ion in solution affect the molar solubility value calculated for the second solution , OThe molar solubility would be too high because the amount of barium in solution is actually higher O The molar solubity cannot change here. O It would appear too low because the molar solubility would be determined using the hydroxide ion concentration and not usingublished K value.

Explanation / Answer

a) if we will not use Ba+2 then the molar solbulity of will be too high due to common ion effect. On adding addition Ba+2 due to common ion the solublity of barium hydroxide decreases.

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.