PART? Chemical Reaction and Conductance Variation Conductance tms) formed Additi

Question

PART? Chemical Reaction and Conductance Variation Conductance tms) formed Addition of 10 ml of a 0.4 M eapita morease sligntv Cl Addition of 10 ml of o 4 MM solution of H SO. to B 20 mL of a 0. 1 M solution of NHs 20 mL of a 0.1 M solution of .lo0 CH COOH Add solution a to solution b5.70 TRIAL 1 1. Explain the conductance change after the addition of Ba(CHaCOO)a to solution A. Write the appropriate chemical equation(s) to support your explanation Explain the conductance change after the addition of HzSO4 to the solution B that contained Ba(CHsCOO)2. Write the appropriate chemical equation(s) to support your explanation. 2 TRIAL 2 3. Explain the conductance change after the mixing the solution of NH3 (a) with solution CHsCOOH (b) to form solution c. Write the appropriate chemical equation(s) to support your explanation

Explanation / Answer

Trail 1

1) Ba(CH3COO)2 is a strong electrolyte and ionizes completely in aqueous solution as below.

Ba(CH3COO)2 (aq) ----------> Ba2+ (aq) + 2 CH3COO- (aq)

Deionized water (H2O) is poorly ionized to proton and hydroxide as below.

H2O (l) <=====> H+ (aq) + OH- (aq)

Due to poor ionization of deionized water, the conductance of deionized water (solution A) is low. The conductance of a solution increases with the increase in the number of ions. When Ba(CH3COO)2 is added to deionized water, Ba(CH3COO)2 is completely ionized and hence, the number of ions increases greatly, thereby, increasing the conductance of the solution. Therefore, solution B registers a high conductance.

2) H2SO4 reacts with Ba(CH3COO)2 as below.

Ba(CH3COO)2 (aq) + H2SO4 (aq) ---------> BaSO4 (s) + 2 CH3COOH (aq)

Adding H2SO4 to solution B precipitates out solid BaSO4 and the solution contains CH3COOH which is a weak acid (poorly ionized in solution). Hence, the number of ions decreases in solution C and thus, the conductance of solution C is much lower than that of solution B.

Trail 2

3) NH3 reacts with CH3COOH to form ammonium acetate (CH3COONH4) as below.

NH3 (aq) + CH3COOH (aq) ---------> CH3COO-NH4+ (aq) + H2O (l)

Solutions a and b are weak electrolytes and hence, poorly ionized in solution. Therefore, the conductances of solutions a and b are low. However, when the two solutions are mixed, an ionic electrolyte, ammonium acetate is formed which ionizes in solution to produce acetate (CH3COO-) and ammonium (NH4+) ions. Since, the number of ions in solution c is higher than those in solutions a and b, the conductance of solution c is higher than these two solutions.

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