A chemical engineer is studying the two reactions shown in the table below In ea

Question

A chemical engineer is studying the two reactions shown in the table below In each case, he fills a reaction vessel with some mixture of the reactants and products at a constant temperature of 109.0 oC an constant total pressure. Then, he measures the reaction enthalpy H and reaction entropy S of the first reaction, and the reaction enthalpy H and reaction free energy G of the second reaction. The results of his measurements are shown in the table. Complete the table. That is, calculate G for the first reaction and AS for the second. (Round your answer to zero decimal places.) Then, decide whether, under the conditions the engineer has set up, the reaction is spontaneous, the reverse reaction is spontaneous, or neither forward nor reverse reaction is spontaneous because the system is at equilibrium Aff= -188. kJ 4S =-492. N2H4(g) + H2(g) 2NH3(g) Which is spontaneous this reaction the reverse o neither AH = 92, kJ 4.S = 2NH3(x) N2(g) + 3H2(g) Which is spontaneous this reaction the reverse o neither

Explanation / Answer

DG = DH - TDS

   T = 109+273.15 = 382.15 k

   = (-188)-(382.15*-492*10^-3)

   = 0.018 kj

as DG = +ve, this reaction is non-spontaenous, reverse reaction spontaneous.

answer: the reverse reaction.

DG = DH - TDS

   T = 109+273.15 = 382.15 k

-29 = (92)-(382.15*x*10^-3)

x = DS = 317 j/mol.k

as DG = -ve, this reaction is aspontaenous, reverse reaction non-spontaneous.

answer: this reaction.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.