A hydrogen-like ion is an ion containing only one electron. The energy of the el

Question

A hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by E n =-(2.18 x 10-18J)22 (1 where n is the principal quantum number and Z is the atomic number of the element Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as H +. Use the equation above to calculate the energy required for the last ionization step: 11g79+(g ) Hg80+(g )+ e-

Explanation / Answer

Last two electrons would always be in the first shell because of 1s in the innermost shell.

Therefore, n = 1

Z= 80

En = - (2.18 x 10-18 J) x Z2 x (1 / n2)

            Or, En = - (2.18 x 10-18 J) x (80)2 x (1 / 12)

            Hence, En = - 1.3952 x 10-14 J.

So,

The required ionization energy = + 1.3952 x 10-14 J. here the +ve sign indicates that energy must be provided for ionization to occurs.

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