The correct answer is D. Can you please explain why? I thought it was B. Barium

Question

The correct answer is D. Can you please explain why? I thought it was B.

Barium carbonate, BaCO3, is stable at ambient temperatures, but decomposes to barium oxide and carbon dioxide at higher temperatures. BaCO3(s)Ba0(s) +CO2(g) At a certain temperature, this system is in equilibrium in a closed system and contains appreciable amounts of all three compounds. Which changes will lead to an increase in the pressure of CO2 present at equilibrium? I. Adding more BaCO,(s) II. Increasing the volume of the container (A) I only (C) Both I and II (B) 11 only (D) Neither I nor II

Explanation / Answer

BaCO3(s) <-------------------> BaO(s) + CO2(g)

here we can see that the BaCO3 is solid and BaO is also solid and we know that the amount of solid will not affect the equilibrium so, simply when we increase the amount of BaCO3 the amount of partial pressure of CO2 will not change because it is fixed.

Kp = P(CO2)

when you increase the volume of the container the number of moles of CO2 is fixed so the partial pressure is fixed and Kp also fixed. but here total pressure will be changed.

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