b) Ca,(PO,)h 3102 (8 pts) If we had one mole of each of the following compounds,

Question

b) Ca,(PO,)h 3102 (8 pts) If we had one mole of each of the following compounds, how many total moles of atoms would we have for 3. each compound? A) C2H4 B) Na SO4 4. (4 pts) How many moles of MgSO, are present in 25.103 g of Ms5o? M24.312 12. (4 pts) Circle any ion(s) below that is (are) isoelectronic with Kr: 223-Ra 15. (4 pts) Identify the reaction type for each of the following reactions: a) Ba(NOs)2iea)+ (NH4)2SO4(a)Baoa+2NH,NO30 b) HCl(aq) + NaOH(aq) NaChaq) + HzOn-M For the following reactions, calculate the oxidation numbers for each element present in the reactants and products and indicate which re 4 agent (if any) is being reduced and which compound is being oxidized. a) 4NHj+ 30 2N2 + 6H2O reactants: N 2. products: N 0 S Identity of Reactant Reduced: 30 Identity of Reactant Oxidized: 2 reactants: CaR_ Identity of Reactant Reduced: Identity of Reactant Oxidized: Ca b) Ca+ ChCaCl Cl products: Ca 2c 350 M solution of LiOH?

Explanation / Answer

3.

(a)

C2H4 has 6 mol of atoms

(b) Na2SO4 has 7 mol of atoms

4.

Mass of MgSO3 = 25.103 g.

Molar mass of MgSO3 = 24 + 32 + 3 (16) = 104 g/mol

Moles of MgSO3 = mass / molar mass = 25.103 / 104 = 0.241 mol

12.

Kr has 36 electrons

Br- has also 36 electrons ( 35 + 1)

So, Kr and Br- are isoelectronic with each other.

15.

(a) Double displacement reaction (or) precipitation reaction

(b) Neutralisation reaction (or) Acid - base reaction

18.

(a)

Reactants side:

N = -3

H = + 1

O = 0

Products side:

N = 0

H + 1

O = - 2

SO, NH3 is oxidised and O2 is reduced.

(b)

Reactants side:

Ca = 0

Cl = 0

Products side:

Ca = + 2

Cl = - 1

SO, Ca is oxidised and Cl2 is reduced.

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