Thermodynamics, Entropy and Gibbs energy 1 Exercise 17.30 2 of 5 Constants | Per
ID: 1031604 • Letter: T
Question
Thermodynamics, Entropy and Gibbs energy 1
Exercise 17.30
2 of 5
Constants | Periodic Table
Without doing any calculations, determine the sign of Ssys and Ssurr for each of the chemical reactions below.
Part A
2CO(g)+O2(g)2CO2(g)rH= -566.0 kJmol1
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Part B
2NO2(g)2NO(g)+O2(g)rH= 113.1 kJmol1
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Part C
2H2(g)+O2(g)2H2O(g)rH= -483.6 kJmol1
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Part D
CO2(g)C(s)+O2(g)rH= 393.5 kJmol1
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Part E
In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction in part A will be spontaneous.
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Part F
In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction in part B will be spontaneous.
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Part G
In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction in part C will be spontaneous.
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Part H
In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction in part D will be spontaneous.
SubmitRequest Answer
Constants | Periodic Table
Without doing any calculations, determine the sign of Ssys and Ssurr for each of the chemical reactions below.
Part A
2CO(g)+O2(g)2CO2(g)rH= -566.0 kJmol1
-566.0 Ssys>0, Ssurr>0 Ssys<0, Ssurr>0 Ssys>0, Ssurr<0 Ssys<0, Ssurr<0SubmitRequest Answer
Part B
2NO2(g)2NO(g)+O2(g)rH= 113.1 kJmol1
113.1 Ssys>0, Ssurr>0 Ssys<0, Ssurr>0 Ssys>0, Ssurr<0 Ssys<0, Ssurr<0SubmitRequest Answer
Part C
2H2(g)+O2(g)2H2O(g)rH= -483.6 kJmol1
-483.6 Ssys>0, Ssurr>0 Ssys<0, Ssurr>0 Ssys>0, Ssurr<0 Ssys<0, Ssurr<0SubmitRequest Answer
Part D
CO2(g)C(s)+O2(g)rH= 393.5 kJmol1
393.5 Ssys>0, Ssurr>0 Ssys<0, Ssurr>0 Ssys>0, Ssurr<0 Ssys<0, Ssurr<0SubmitRequest Answer
Part E
In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction in part A will be spontaneous.
In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction in part A will be spontaneous. The reaction is spontaneous at all temperatures. The reaction is spontaneous at low temperatures. The reaction is spontaneous at high temperatures. The reaction is nonspontaneous at all temperatures.SubmitRequest Answer
Part F
In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction in part B will be spontaneous.
In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction in part B will be spontaneous. The reaction is spontaneous at all temperatures. The reaction is spontaneous at low temperatures. The reaction is spontaneous at high temperatures. The reaction is nonspontaneous at all temperatures.SubmitRequest Answer
Part G
In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction in part C will be spontaneous.
In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction in part C will be spontaneous. The reaction is spontaneous at all temperatures. The reaction is spontaneous at low temperatures. The reaction is spontaneous at high temperatures. The reaction is nonspontaneous at all temperatures.SubmitRequest Answer
Part H
In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction in part D will be spontaneous.
In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction in part D will be spontaneous. The reaction is spontaneous at all temperatures. The reaction is spontaneous at low temperatures. The reaction is spontaneous at high temperatures. The reaction is nonspontaneous at all temperatures.SubmitRequest Answer
Explanation / Answer
PART A: THE NO OF MOLECULES IS DECREASING UP ON REACTION SO THE SSYS IS DECRESING I.E SSYS<0 AND SSURR>0.
PART B: THE NO OF MOLECULES IS INCRESING UP ON REACTION SO THE SSYS IS DECRESING I.E SSYS>
0 AND SSURR<0.
PART C: THE NO OF MOLECULES IS DECREASING UP ON REACTION SO THE SSYS IS DECRESING I.E SSYS<0 AND SSURR>0.
PART D: THE NO OF MOLECULES IS INCRESING UP ON REACTION SO THE SSYS IS DECRESING I.E SSYS>
0 AND SSURR<0.
PART E:FOR THE REACTION OF PART A THE H=-VE AND SSYS=+VE SO THE RESCTION IS SPONTENIOUS AT ALL TEMPERATURES.
PART F:FOR THE REACTION OF PART A THE H=+VE AND SSYS=-VE SO THE RESCTION IS NONSPONTENIOUS AT ALL TEMPERATURES.
PART G:FOR THE REACTION OF PART A THE H=-VE AND SSYS=_VE SO THE RESCTION IS SPONTENIOUS AT LOW TEMPERATURES.
PART H:FOR THE REACTION OF PART A THE H=+VE AND SSYS=+VE SO THE RESCTION IS SPONTENIOUS AT HIGH TEMPERATURES.
G=H-TS.IF THE VALUE OF G IS NEGATIVE THE REACTION WILL BE SPONTENEOUS.
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