3.) for each of the following strong acid/base solutions, calculate the [OH-], [

Question

3.) for each of the following strong acid/base solutions, calculate the [OH-], [H+], ph and pOH
4.) fill in the blanks 3.) For each of the following strong acid/base solutions, calculate the (OH1. [H'1, pH and pOH: a. 0.250 M NaOH b. 8.55 M HNO c. 8.65 x 10 M Ba(OH)2 d. 2.55 M HClO4 4.) Fill in the blanks (all acids are weak, all concentrations are at equilibrium): HAH+A Ka 1.0 x 102 Acid Chlorous acid 1.60 M 0.127 M Nitrous acid 11.6 M 0.050 M 0.10 M Hydrocyanic acid 1.4x 104 M 1.0 x 104 M 4.9 x 10-0 Phosphoric acid 0.038 0.15 7.6 x 103

Explanation / Answer

3) a) 0.25 M NaOH

[OH-] = 0.25 M

pOH = -log(OH-)

     = -log0.25

     = 0.6

kW = [H+][OH-]

[H+] = 10^-14/0.25 = 4*10^-14 M

pH = -log(H+)

    = -log(4*10^-14)

    = 13.4

b) 8.55 HNO3

kW = [H+][OH-]

[H+] = 8.55 M

pH = -log(H+)

    = -log(8.55)

    = -0.93

[OH-] = 10^-14/8.55 = 1.17*10^-15 M

pOH = -log(OH-)

     = -log(1.17*10^-15)

     = 14.93

c) 8.65*10^-3 Ba(OH)2

[oh-] = 8.65*10^-3*2 = 1.73*10^-2 M

pOH = -log(1.73*10^-2) = 1.762

kW = [H+][OH-]

[H+] = 10^-14/(1.73*10^-2)

       = 5.78*10^-13 M

pH = -log(H+)

    = -log(5.78*10^-13)

   = 12.24

d)

kW = [H+][OH-]

[H+] = 2.55 M

pH = -log(H+)

    = -log(2.55)

    = -0.4

[OH-] = 10^-14/2.55 = 3.92*10^-15 M

pOH = -log(OH-)

     = -log(3.92*10^-15)

     = 14.4

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