ANSWER ALL PARTS OF THIS QUESTION Jump to... Calculator Periodic Table Question

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Jump to... Calculator Periodic Table Question 4 of 17 Sapling Learning Map Consider a solution containing 3.89 mM of an analyte, X, and 1.08 mM of a standard, S. Upon chromatographic separation of the solution peak areas for X and S are 3991 and 10217, respectively Determine the response factor for X relative to S Number the uelerowne the concentration of Xin an unknown solution. 1,00 mL of 8.76 mM S was added to 3.00 mL of the unknown X solution and the mixture was diluted to 10.0 mL. After chromatographic solution gave peak areas of 5643 and 4613 for X and S, respectively Determine the concentration of S in the 10.0 mL solution. Number mM Determine the concentration of X in the 10.0 mL solution. Number m M Determine the concentration of X in the unknown solution. RrmdousGive Up & View Solution Check Answer Next Exit

Explanation / Answer

1)

we know that

response factor = peak area / concentration

so

RF for X = 3991 / 3.89 = 1025.96

RF for S = 10217 / 1.08 =9460.185

now,relative response facotr (RRF) = RF of X / RF of S

RRF = 1025.96 / 9460.185

RRF = 0.108

so,the response facoter for X relative to S is 0.108

2)

we know tha

for dilution

M1V1 = M2V2

so for standard S ,

1 x 8.76 = 10 x M2

M2=0.876

so,the concentration of S in the 10 ml solution = 0.876

now

RF for S = peak area / conc

RF for S = 5643 / 0.876

RF for S = 6441.78

now,RFF = RF for X / RF for S

0.108 = RF for X / 6441.78

RF for X = 695.71

now,RF for X = peak area / conc

695.71 = 4613 / conc

concentration of X = 6.63

so,the concentration of X in the 10 ml solution is 6.63 mM

now

for dilution

M1V1 = M2V2

so, M1 x 3 = 6.63 x 10

M1 = 22.1

so,the concentration of X in the unknown solution is 22.1 mM

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