2- | Sapling Learning macmillan learning Consider this reaction data: If you wer

Question

2-

| Sapling Learning macmillan learning Consider this reaction data: If you were going to graphically determine the activation energy of this reaction, what points would you plot? A > products X Number Number T (K) k (S-1) 0.387 0.885 275 725 point 1: To avoid rounding errors, use at least three significant figures in all values. Number Number point 2: Determine the rise, run, and slope of the line formed by these points. rise run slope Number Number Number ÉÉÉ What is the activation energy of this reaction? Number J/mol 2 Previous ( Check Answer Nevt. I evit

Explanation / Answer

we need

ln(K)= and 1/T

point 1:

x = 1/T = 1/275 = 0.00363

y = ln(k) = ln(0.387) = -0.9493

point 2:

x = 1/T = 1/725= 0.0013793

y = ln(k) = ln(0.885) = -0.1221

rise = -0.1221 - -0.9493 = 0.8272

run = 0.0013793-0.00363 = -0.00225

slope = 0.8272/-0.00225 = -367.644

-Ea/R = slope

Ea = -R*slope = -8.314*-367.644 = 3056.59J/mol

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